Answer:
distance = 10.8 units
midpoint: (5, -4)
Step-by-step explanation:
To find distance
[tex]\sf d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}[/tex]
[tex]\sf d = \sqrt{(-2 -(-6))^2 + (0 -10)^2}[/tex]
[tex]\sf d = \sqrt{(4)^2 + (-10)^2}[/tex]
[tex]\sf d = \sqrt{16+ 100}[/tex]
[tex]\sf d = \sqrt{116}\quad \approx \quad 10.8[/tex]
To find midpoint
[tex]\sf (x_m, y_m) = \left(\dfrac{x_1+x_2}{2}, \dfrac{y_1+y_2}{2}\right)[/tex]
[tex]\sf (x_m, y_m) = \left(\dfrac{10+0}{2}, \dfrac{-6-2}{2}\right) = (5, -4)[/tex]
