Given:
The right angled triangle with a side equal to 5 units and hypotenuse equal to 13 units is given.
To find the third side, we will apply Pythagoras theorem, that is,
[tex]\text{Hypotenuse}^2=base^2+perpendicular^2[/tex]
Substituting the values, we get:
[tex]\begin{gathered} 13^2=5^2+perpendicular^2 \\ \text{Perpendicular}^2=13^2-5^2 \\ =169-25 \\ =144 \\ \text{perpendicular}=\sqrt[]{144} \\ =12 \end{gathered}[/tex]
Therefore, the missing side is 12 units.
