Given:
There are given that the solutions of x are 3 and -7.
Explanation:
From the given value of x,
[tex]\begin{gathered} x-3=0\text{ and} \\ x+7=0 \end{gathered}[/tex]
Then, two binomials that make up the quadratic are:
[tex](x-3)(x+7)=0[/tex]
Then,
Solve the above factor:
[tex]\begin{gathered} (x-3)(x+7)=0 \\ x^2+7x-3x-(3)(7)=0 \\ x^2+4x-21=0 \end{gathered}[/tex]
Final answer:
Hence, the quadratic equation is shown below;
[tex]x^2+4x-21=0[/tex]
