let us put the first equation y = 6x -11 into the second equation and we get
[tex]-2x-3(6x-11)=-7[/tex]
Simplifies the above gives
[tex]-2x-18x+33=-7[/tex][tex]-20x=-40[/tex][tex]\textcolor{#FF7968}{\therefore x=2.}[/tex]
Using this value of x in y = 6x - 11 gives
[tex]y=6(2)-11[/tex][tex]\textcolor{#FF7968}{\therefore y=1.}[/tex]
Finally, we put in x = 2 and y = 1 into the last equation and solve for z.
[tex]3(2)-5(1)+6z=25[/tex][tex]6z=24[/tex][tex]\textcolor{#FF7968}{\therefore z=4.}[/tex]
Hence, our solution is (x, y, z) = (2, 1, 4).
