Answer:
[tex]y\text{ = -}\frac{1}{3}[/tex]
Explanation:
Here, we want to solve the given equation for y
The approach to this is to make sure we have equal bases on both sides
Thus, we have it that:
[tex]8^{6y+4}=8^2[/tex]
From here, we have to equate the powers since we have same base on both sides
Thus, we have it that:
[tex]\begin{gathered} 6y\text{ + 4 = 2} \\ 6y\text{ = 2-4} \\ 6y\text{ = -2} \\ y\text{ = -}\frac{2}{6}\text{ = -}\frac{1}{3} \end{gathered}[/tex]
