Given:
Decay rate = 8% per day = 0.08
Initial mass = 2.43 kg
Let's find the mass of the sample after 3 days.
Apply the exponential decay formula:
[tex]A=P_oe^{-rt}[/tex]Where:
A is the final amount
Po is the initial amount = 2.43
r is the rate = 0.08
t is the time = 3 days.
Thus, we have:
[tex]\begin{gathered} A=2.43e^{-0.08*3} \\ \\ A=2.43(0.78662) \\ \\ A=1.91 \end{gathered}[/tex]Therefore, the mass of the sample after 3 days is 1.91 kg.
ANSWER:
1.91 kg