SOLUTION
The given equation is
[tex]x^3+3x^2-16x-48=0[/tex]
From the given graph, one of the solution of the equation is
[tex]x=4[/tex]
Since x=4 is a solution to the equation it follows that x-4 is a factor
The given equatin can be simplified as
[tex]x^3+3x^2-16x-48=(x-4)(x+4)(x+3)[/tex]
Therefefore other solutions are
[tex]x=-4,x=-3[/tex]
