Respuesta :
Given:
• Length of wire = 3.0 cm
,• Current = 10 A
,• Magnetic field = 0.27 T
Let's find the magnetic force on the wire.
To find the magnetic force on the wire, apply the formula:
[tex]F=BILsin\theta[/tex]Where:
B is the magnetic field = 0.27 T
I is the current = 10 A
L is the length of wire in meters = 3.0 cm = 0.03 m
Since it is perpendicular, θ = 90 degrees.
F is the magnetic force.
Substitute the values into the formula and solve for F.
We have:
[tex]\begin{gathered} F=0.27*10*0.03sin90 \\ \\ F=0.27*10*0.03(1) \\ \\ F=0.081\text{ N} \\ \\ F=8.1\times10^{-2}N \end{gathered}[/tex]Therefore, the magnetic force on the wire is 8.1 x 10⁻² N.
ANSWER:
8.1 x 10⁻² N
