Given:-
[tex]\log (x-2)+\log (2x-3)=2\log x[/tex]
To find:-
Prove the above statement.
To prove the above statement we use the formula,
[tex]\log a+\log b=\log ab[/tex]
So we get,
[tex]\begin{gathered} \log (x-2)+\log (2x-3)=\log \lbrack(x-2)(2x-3)\rbrack \\ \text{ =log\lbrack{}2x}^2-3x-4x+6\rbrack \end{gathered}[/tex]
By simplyfying futhur we get,
