Given:
The mass of the ball is,
[tex]m=4\text{ kg}[/tex]The initial velocity of the ball is,
[tex]v_i=10\text{ m/s}[/tex]The angle with the floor is,
[tex]\theta=37^{\circ}[/tex]The change in momentum is the impulse by the floor, so the impulse is,
[tex]\begin{gathered} P=m(v_f-v_i) \\ =4\lbrack10-(-10\rbrack \\ =80\text{ kg m/s} \end{gathered}[/tex]The impulse is 80 kgm/s along with the final velocity.
