Respuesta :

[tex]\begin{gathered} \text{Thr circumference of the circle is}\Rightarrow16\pi \\ So, \\ 2\pi r=16\pi \\ r=8m \\ \text{Now, The area of circle is} \\ Area=\pi r^2 \\ \text{Area}=\pi\times8^2 \\ Area=64\pi(\text{Ans)} \end{gathered}[/tex]

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