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1404 0. An automobile's velocity, starting from a complete stop, is v(t) =5t - 6 where vis measured in feet per second. After what elapsed time would the automobile reach a velocity of 44 feet per second?

Respuesta :

We have

[tex]v(t)=5t-6[/tex]

where v is the velocity and t is the time

we have

v =44 ft per second

we need to substitute the values given in the equation given

[tex]44=5t-6[/tex]

then we isolate t

[tex]\begin{gathered} 5t=44+6 \\ 5t=50 \\ t=\frac{50}{5} \\ t=10\sec \end{gathered}[/tex]

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