ABC is congruent to DEF, so
[tex]\begin{gathered} \angle A=\angle D \\ \angle B=\angle E \\ \angle C=\angle F \end{gathered}[/tex]Given A = 50 and E = 30, we need to find C=?
A = 50
E = 30 means B = 30
So, now we can find c.
Triangle ABC has angles A, B, and C.
All 3 angles add up to 180. So we can write and solve:
[tex]\begin{gathered} \angle A+\angle B+\angle C=180 \\ 50+30+\angle C=180 \\ 80+\angle C=180 \\ \angle C=100\degree \end{gathered}[/tex]