The acid ionization constant of a solution is represented as Ka. The Pka is the negative logarithm of Ka value. The ka value of the acid with pka of 5.2 is 6.3 × 10⁻⁶ .
Acid ionization constant is the ratio of product of concentration of the ions in the acid to the molar concentration of the acid.
If and cid HA ionizes into H+ and A- then ionization constant Ka is written as follows:
Ka = [A-] [H+] / [HA]
Mathematically pka is the negative logarithm of ka value. The pka value is given 5.2 thus ka value is calculated as follows:
pka = -log (Ka)
- 5.2 = log (Ka)
Ka = antilog (5.2)
= 6.3 × 10⁻⁶.
Therefore, ka value of the acid with pka of 5.2 is 6.3 × 10⁻⁶ .
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