First, we need to find the total current. We can do this using ohm's law:
[tex]\begin{gathered} I=\frac{V}{R} \\ where: \\ V=12V \\ \frac{1}{R}=\frac{1}{R1}+\frac{1}{R2}+\frac{1}{R3}=\frac{1}{6}+\frac{1}{6}+\frac{1}{6}=\frac{1}{2} \\ \\ R=2\Omega \end{gathered}[/tex][tex]I=\frac{12}{2}=6A[/tex]Now, the current through each resistor is given by:
[tex]\begin{gathered} I_1=\frac{I}{3}=\frac{6}{3}=2A \\ or \\ I_1=\frac{12}{6}=2A \end{gathered}[/tex]Answer:
c.
2 Amps
