ANSWER:
The x-component of this vector is -22.7 m
The y-component of this vector is 13.1
STEP-BY-STEP EXPLANATION:
Given:
Magnitude: 26.2 m
Direction: 60°
The first thing is to make a sketch of the situation like this:
x-component of vector Z is:
[tex]\begin{gathered} Z_x=-Z\cdot\sin \theta \\ Z_x=-26.2\cdot\sin 60 \\ Z_x=-22.7\text{ m} \end{gathered}[/tex]y-component of vector Z is:
[tex]\begin{gathered} Z_y=Z\cdot\cos \theta \\ Z_y=26.2\cdot\cos 60 \\ Z_y=13.1\text{ m} \end{gathered}[/tex]
