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Ray and Jon play a game of chance with two dice. If the sum of thedice is seven, Ray pays Jon $15. But if the sum is anything else,Jon pays Ray $10. What is the expected value of the game for Jon?Answer:-5.83

Respuesta :

Given:

Two dice are rolled. n(S)=36

Let A be an event of getting a sum of 7.

[tex]A=\mleft\lbrace(1,6\mright),(2,5),(3,4),(4,3),(5,2),(6,1)\}[/tex][tex]n(A)=6[/tex][tex]P(A)=\frac{n(A)}{n(S)}[/tex][tex]P(A)=\frac{6}{36}[/tex][tex]P(A)=0.1667[/tex][tex]\text{The expected value of the game for Jon =}\frac{6}{36}\times10[/tex][tex]\text{The expected value of the game for Jon = \$}1.667[/tex]

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