Given:
The scores on a test are normally distributed.
The mean = μ = 80
The standard deviation = σ = 16
we will find the score that is 2 1/2 standard deviations above the mean
Le the score = x, so, z = 2 1/2
We will use the following formula to find x
[tex]x=\mu\pm z\sigma[/tex]
substitute the given values
[tex]x=80+2.5*16=120[/tex]
So, the answer will be:
A score of 120 is 2 1/2 standard deviations above the mean.
