Given data
The wavelength of the starlight is lambda 2 = 97 nanometers
The expression for the photon energy is given as:
[tex]E=\frac{hc}{\lambda_2}[/tex]Substitute the value in the above equation.
[tex]\begin{gathered} E=\frac{4.136\times10^{-15}\text{ eVs }\times3\times10^8\text{ m/s}}{97\text{ nm}}\times\frac{1\text{ nm}}{10^{-9}\text{ m}} \\ E=12.79\text{ eV} \end{gathered}[/tex]Thus, the photon energy is 12.79 eV.
