Given
[tex]f(x)=\frac{x(x-2)}{(x+3)(x-5)}[/tex]
Solution
Set f(x) = 0
[tex]\begin{gathered} 0=\frac{x(x-2)}{(x+3)(x-5)} \\ Rewrite \\ \frac{x(x-2)}{(x+3)(x-5)}=0 \\ cross\text{ multiply} \\ We\text{ have} \\ x(x-2)=0 \\ x=0 \\ x=2 \end{gathered}[/tex]
The final answer
