Respuesta :

[tex]9x-8>4x+7[/tex]

Move the "x" terms to the right

[tex]9x-4x>7+8[/tex][tex]5x>15[/tex]

Divide both sides by 5:

[tex]\frac{5x}{5}>\frac{15}{5}[/tex][tex]x>3[/tex]