A survey conducted about the colors of shoes that people were wearingg

Given:
Find-: Probability that a randomly selected person was either female or was wearing brown shoes.
Sol:
The probability that the randomly selected person was female.
Total female :
[tex]\begin{gathered} =4+11+16+2 \\ =33 \end{gathered}[/tex]Total = male +female
[tex]\begin{gathered} =31+33 \\ =64 \end{gathered}[/tex]Probability:
[tex]\begin{gathered} P(A)=\frac{\text{Favorable conditions}}{\text{ total conditions}} \\ P(A)=\frac{33}{64} \end{gathered}[/tex]The probability that a randomly selected person was wearing brown shoes.
Total brown shoes:
[tex]\begin{gathered} =7+11 \\ =18 \end{gathered}[/tex]Total shoes:
[tex]=64[/tex]Probability :
[tex]P(B)=\frac{18}{64}[/tex]The probability that a randomly selected person was either female or was wearing brown shoes.
[tex]\begin{gathered} P=P(A)+P(B) \\ =\frac{33}{64}+\frac{18}{64} \\ =\frac{51}{64} \\ =0.797 \end{gathered}[/tex]So the probabili