In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
triangle 1
h = 6
p = 18
triangle 2
h = 4
p = ?
Step 02:
We must apply the properties of triangles to find the solution.
[tex]\frac{ht2}{ht1}=\frac{pt2}{pt1}[/tex][tex]\frac{4}{6}=\frac{pt2}{18}[/tex]18*4 = 6 * pt2
72 = 6 pt2
72 / 6 = pt2
12 = pt2
The answer is:
The perimeter of the smaller triangle is 12