To answer this question, we have to use the ideal gas law:
[tex]PV=nRT[/tex]Where P is pressure, V is volume, n is the number of moles, R is the constant of ideal gases (0.082atmL/molK) and T is the temperature (in Kelvin degrees).
Convert the given temperature to Kelvin degrees:
[tex]T=27+273.15=300.15[/tex]Solve the equation for P and replace for the given values:
[tex]\begin{gathered} P=\frac{nRT}{V} \\ P=\frac{2.43mol\cdot0.082atmL/molK\cdot300.15K}{10.0L} \\ P=5.98atm \end{gathered}[/tex]It means that the pressure of helium is 5.98atm.
