We need to solve the next summation:
[tex]\sum_{i\mathop{=}2}^5(-1-2i)[/tex]
i represents the value where we start and 5 represents the value where we need to go.
So, we need to sum by changing the i variable starting with 2 until 5.
Then:
[tex]\begin{gathered} \sum_{i\mathop{=}2}^5(-1-2i)=(-1-2(2))+(-1-2(3))+(-1-2(4))+(-1-2(5)) \\ =-5+(-7)+(-9)+(-11) \\ =-5-7-9-11 \\ =-32 \end{gathered}[/tex]
Hence, the answer is -32.
