Respuesta :
The quadratic formula can be expressed as a function of its zeros:
[tex]y(x)\text{ = a}\cdot(x-x_1)\cdot(x_{}-x_2)[/tex]Where x1 and x2 are the zeros of the equation and "a" is a constant.
[tex]\begin{gathered} y(x)\text{ = a}\cdot(x\text{ - (-4))}\cdot(x-1) \\ y(x)\text{ = a}\cdot(x+4)\cdot(x-1) \end{gathered}[/tex]To find the constant we need to apply the point (-3,-4).
[tex]\begin{gathered} -4\text{ = a}\cdot(-3+4)\cdot(-3-1) \\ -4\text{ = a}\cdot(1)\cdot(-4) \\ -4=-4a \\ a\text{ = }\frac{-4}{-4}\text{ = 1} \end{gathered}[/tex]Therefore the quadratic expression:
[tex]\begin{gathered} y(x)=(x+4)\cdot(x-1) \\ y(x)=x^2-x+4x-4 \\ y(x)=x^2+3x-4 \end{gathered}[/tex]