Respuesta :

Answer:

[tex]\frac{11y-110}{50-5y}=-\frac{11}{5}[/tex]

Explanations:

Given the following expression show below;

[tex]\frac{11y-110}{50-5y}[/tex]

Factor out the GCF from both the numerator and denominator

[tex]\frac{11(y-10)}{5(10-y)}[/tex]

This can also be expressed as;

[tex]\begin{gathered} \frac{11(-10+y)}{5(10-y)} \\ \frac{-11(10-y)}{5(10-y)} \end{gathered}[/tex]

Cancel out the common expression

[tex]\frac{-11\cancel{(10-y)}}{5\cancel{(10-y)}}=-\frac{11}{5}[/tex]

Hence the simplified form of the expression is -11/5