Given:
A vector with a magnitude 8 and a direction 120°
The component form of the vector will be as follows:
[tex]\begin{gathered} x-component=8*cos(120)=8*(-\frac{1}{2})=-4 \\ y-component=8*sin(120)=8*(\frac{\sqrt{3}}{2})=4\sqrt{3} \end{gathered}[/tex]So, the answer will be, the given vector will be as follows:
[tex]v=<-4,4\sqrt{3}>[/tex]