Given:
One week a computer store sold a total of 36 computers and external hard drives.
Let the number of computers = x
And the number of the external hard drives = y
so, we can write the following equation:
[tex]x+y=36\rightarrow(1)[/tex]The revenue from these sales was 29,820. If computers sold for 1180 and hard drives for 125 per unit
So, we can write the following equation:
[tex]1180x+125y=29820\rightarrow(2)[/tex]We will solve the equations (1) and (2) to find (x) and (y):
from equation (1):
[tex]y=36-x\operatorname{\rightarrow}(3)[/tex]Substitute (y) from equation (3) into equation (2) and then solve for (x):
[tex]\begin{gathered} 1180x+125(36-x)=29820 \\ 1180x+125*36-125x=29820 \\ 1180x-125x=29820-125*36 \\ 1055x=25320 \\ \\ x=\frac{25320}{1055}=24 \end{gathered}[/tex]Substitute (x) into equation (3) to find (y):
[tex]y=36-24=12[/tex]So, the answer will be:
The number of computers sold = 24
The number of hard drives sold = 12