We have to think this problem as if it were a quadratic function. In order to fin the numbers that multiplied give as result 12 and added give as result 7, we will solve:
[tex]f(x)=x^2+7x+12[/tex]
So, we factor as follows:
[tex]f(x)=(x+4)(x+3)[/tex]
Now, we have that the numbers that multiplied give as result 12 and added give as result 7, are 4 & 3.
