For our first inequality
1. x + 5 < 6
collect like terms
x < 6 - 5
x < 1
2.
[tex]\begin{gathered} 9x\ge3 \\ \text{divide both sides by 9} \\ x\ge\frac{3}{9} \\ x\ge\frac{1}{3} \end{gathered}[/tex]3.
[tex]\begin{gathered} \frac{x}{9}\leq1 \\ \text{cross multiply} \\ x\leq9 \end{gathered}[/tex]