Given:
The number of democrats = 5.
The number of republicans = 6.
Aim:
We need to find the probability of selecting four Democrats and two Republicans.
Explantion:
The possible way to select four Democrats
[tex]=5C_4=5[/tex]The possible way to select 2 republicans is
[tex]=6C_2=15[/tex]The total way to select 6 people is
[tex]=11C_6=462[/tex]The probability of selecting four Democrats and two Republicans is
[tex]=\frac{5C_4\cdot6C_2}{11C_6}[/tex][tex]=\frac{5\times15}{462}[/tex][tex]=\frac{75}{462}=\frac{25}{154}[/tex]The probability of selecting four Democrats and two Republicans is 25/154.
Final answer:
The probability of selecting four Democrats and two Republicans is 25/154.
