Given that the mass of the box, m = 22.5 Kg
A horizontal force, F = 35.2 N is applied to the wooden box.
A normal force acts upwards, whose value = mg
Here, g is the acceleration due to gravity whose value is 9.8 m/s^2
The formula to find the coefficient of friction is
[tex]\mu=\frac{F}{mg}[/tex]Substituting the values, we get
[tex]\begin{gathered} \mu=\frac{35.2}{22.5\times9.8} \\ =0.159 \end{gathered}[/tex]Thus, the coefficient of friction between the box and the street is 0.159
