Given
x = 1.02 m
t = 1.20s
y = 1m
Procedure
The time of flight of a projectile motion is the time from when the object is projected to the time it reaches the surface.
The maximum height is reached when vy = 0 Using this we can rearrange the velocity equation to find the time it will take for the object to reach maximum height
[tex]\begin{gathered} t=\frac{v_y}{g} \\ t=\frac{5.88\text{ m/s}}{9.81\text{ m/s}^2} \\ t=0.6s \end{gathered}[/tex]