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solve for x and show your steps. Is the solution extraneous? Check your work to show how you determined is the solution is extraneous or not. sqre rt.3x+12=9

Respuesta :

Given:

[tex]\sqrt[]{3x+12}=9[/tex]

Sol:.

[tex]\begin{gathered} \sqrt[]{3x+12}=9 \\ \text{Square both side} \\ 3x+12=81 \\ 3x=81-12 \\ 3x=69 \\ x=\frac{69}{3} \\ x=23 \end{gathered}[/tex]

It is a not extraneous sol.

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