Since we have 6 numbers in the die, the probability of landing each number is 1/6.
For the first roll, we want any number greater than 1, so we have 5 options, therefore the probability is 5/6.
For the second roll, we have 3 options (2, 3 and 5), so the probability is 3/6.
Then, the final probability will be the product of each case probability:
[tex]P=\frac{5}{6}\cdot\frac{3}{6}=\frac{5}{12}[/tex]