To find the plane’s ground speed, we need to solve the next:
Where the plane’s ground speed is given by the red vector.
Then:
[tex]R^2=450^2+50^2-(2(450)(50)(\cos\theta)[/tex]
Where we use cos45.
[tex]\begin{gathered} R^2=202500+2500-30547.01295 \\ R=\sqrt[]{291600+2500-30547.01295} \\ R=505.9 \end{gathered}[/tex]
Hence, the correct answer is option a.
