Given:
[tex]SA=2πrh+2πr^2[/tex]To add:
Explanation:
There is a common factor in both terms.
[tex]2πr[/tex]Let the common factor outside the bracket.
We get,
[tex]SA=2\pi r(h+r)[/tex]Final answer:
The surface area will be,
[tex]SA=2\pi r(h+r)[/tex]