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In a science museum, you may have seen a Foucault pendulum, which is used to demonstrate the rotation of the earth. In one museum's pendulum, the 120 kg bob swings from a 17.4-m-long cable with an amplitude of 5.5 degrees. The period of the pendulum is 8.37 s.What is the bob's maximum speed?

Respuesta :

We have the next information

m=120 kg

l=17.4m

θ=5.5°

T=8.37s

Then for the speed

[tex]\text{Maximum speed=A}\omega[/tex]

For A is the amplitude and omega is the angular speed

[tex]A=l\sin \theta[/tex][tex]\omega=\frac{2\pi}{T}[/tex]

We substitute

[tex]A=17.4\sin (5.5)=1.67m[/tex][tex]\omega=\frac{2\pi}{8.37}=0.75[/tex][tex]\text{Maximum speed=1.67(0.75)=1.25 m/s}[/tex]

ANSWER

Maximum speed 1.25 m/s

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