Given,
Force, F = 380 N
Mass, M = 38 kg
Distance, d = 2.5 m
The work done on the body is equal to the final kinetic energy.
[tex]F\times d=\frac{1}{2}mv^2[/tex]Put the given values in the formula,
[tex]\begin{gathered} 380\text{ N}\times2.5\text{ m = }\frac{1}{2}\times38kg\times v^2 \\ v^2=\frac{950\times2}{38} \\ v^2=50 \\ v=\sqrt[]{50} \end{gathered}[/tex]Thus, the speed of the object after it accelerates is
[tex]v=7.07\text{ m/s}[/tex]