Since the given triangle is isosceles then the base angles are congruent. This means that angle CBA=BCA=25 degrees, that is,
Since interior angles of any triangle add up to 180 degrees, we get
[tex]m\angle CAB+23+23=180[/tex]
which gives
[tex]m\angle CAB+46=180[/tex]
By substracting 46 to both sides, we obtain
[tex]m\angle CAB=134[/tex]
Therefore, the size of angle CAB is 134 degrees
