Given the expression:
[tex]-6(c+4)+3c<\frac{2(4-3)}{2+2}[/tex]Solve for c
[tex]\begin{gathered} -6c-6\cdot4+3c<\frac{2\cdot1}{4} \\ -6c-24+3c<\frac{1}{2} \\ -6c+3c<\frac{1}{2}+24 \\ -3c<\frac{49}{2} \\ \\ c>-\frac{1}{3}\cdot\frac{49}{2} \\ \\ C>-\frac{49}{6} \end{gathered}[/tex]So, the answer will be C > -49/6
