Respuesta :

Given:

[tex](3a^2+5a-2)(5a^2-3a+4)[/tex]

Horizonatal method:

[tex]\begin{gathered} (3a^2+5a-2)(5a^2-3a+4) \\ =3a^2(5a^2-3a+4)+5a(5a^2-3a+4)-2(5a^2-3a+4) \\ =15a^4-9a^3+12a^2+25a^3-15a^2+20a-10a^2+6a-8 \\ =15a^4+16a^3-13a^2+26a-8 \end{gathered}[/tex]

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