Recall that the standard form of a complex number is as follows:
[tex]a+ib.[/tex]
To take the given number to its standard form, we multiply
[tex](9+3i)[/tex]
by itself using the distributive property:
[tex](9+3i)(9+3i)=9(9+3i)+3i(9+3i)=81+27i+27i+9i^2.[/tex]
Simplifying the above result, we get:
[tex]\begin{gathered} 81+54i-9, \\ 72+54i. \end{gathered}[/tex]
Answer:
[tex]72+54\imaginaryI.[/tex]
