Given the system of equations:
[tex]\begin{gathered} y-4x=0\rightarrow(1) \\ 3x+6y=9\rightarrow(2) \end{gathered}[/tex]From equation (1), y = 4x
Substitute with y in the equation (2), then solve for x
[tex]\begin{gathered} 3x+6\cdot4x=9 \\ 3x+24x=9 \\ 27x=9 \\ x=\frac{9}{27} \\ \\ x=\frac{1}{3} \end{gathered}[/tex]So, y = 4x = 4 * 1/3 = 4/3
So, the answer will be option B) x = 1/3 , y = 4/3
