Respuesta :
Given data:
13 red marbles
24 blue marbles
Total marbles:37
probability that both are red P(r,r)
[tex]\begin{gathered} P(r,r)=P(r_1)\cdot P(r_2) \\ \\ P(r_1)=\frac{\#red\text{ marbles}}{\#total\text{ marbles}}=\frac{13}{37} \\ \\ IntheP(r_2)\text{ the number of red marbles is one less the initial (as the frist marble } \\ \text{is red }and\text{ it is outside the jar)} \\ \\ P(r_2)=\frac{#red\text{ marbles}}{#total\text{ marbles}}=\frac{12}{37} \\ \\ \\ \\ P(r,r)=\frac{13}{37}\cdot\frac{12}{37}=\frac{156}{1369}=0.114 \end{gathered}[/tex]Then, the probability of pull out 2 red marbles is 0.114 (11.4%)