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The amount of a radioactive isotope present at time t is given by A(t)=800e−0.02884t grams, where t is the time in years that the isotope decays. The initial amount present is 800 grams. Complete parts (a) through (c)You have to complete a to get b and And complete b to get c. This problem has 3 steps

The amount of a radioactive isotope present at time t is given by At800e002884t grams where t is the time in years that the isotope decays The initial amount pr class=

Respuesta :

(a) You know that this function represents the amount of a radioactive isotope present at time "t" (in years):

[tex]A\mleft(t\mright)=800e^{-0.02884t}[/tex]

Then, in order to find the number of grams remain after 15 years, you need to set up that:

[tex]t=15[/tex]

Now you need to substitute this value into the function and evaluate:

[tex]\begin{gathered} A(15)=800e^{(-0.02884)(15)} \\ A(15)\approx519.06 \\ \end{gathered}[/tex]

(b

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