EjazT475819 EjazT475819

29-10-2022
Mathematics

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A 12.8 mm 110°C find the area of the sector formed

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RogueO590919 RogueO590919

29-10-2022

Since 110 degress is equal to 11pi/18 then the area is

[tex](12.8)^2(\frac{11\pi}{18})(\frac{1}{2})=(81.92)(\frac{11\pi}{18})=157.275mm^2[/tex]

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