The given quadratic equation is,
[tex]3x^2-9x+4=0[/tex]The quadratic can be solved as,
[tex]\begin{gathered} x=\frac{-(-9)\pm\sqrt[]{(-9)^2-4\times3\times4}}{2\times3} \\ =\frac{9\pm\sqrt[]{33}}{6} \\ =\frac{9+\sqrt[]{33}}{6},\frac{9-\sqrt[]{33}}{6} \\ = \end{gathered}[/tex]Thus, the above expression gives the solution of the quadratic equation.
