As given by the question
There are given that the 5000 piece puzzle
Now,
Initially at the time (t)=0 days, the number of pieces of the puzzle was 5000
If there are y remaining pieces of puzzles to fit after d days of the work and the number of the puzzle that Nola fits together each day is p pieces, then we can write the equation that models the situation as:
[tex]y=5000-pd[/tex]
Hence, the algebraic expression is; y = 5000-pd.
